Answer:
8861.75 m approximately 8862 m
Explanation:
We need to remember Newton's 2nd Law which says that the force experienced by an object is proportional to his acceleration and that the constant of proportionality between those two vectors correspond to the mass of the object.
for the weight of an object (which is a force) we have that the acceleration experienced by that object is equal to the gravitational acceleration, obtaining that 
For simplicity we work with
despiting the effect of the height above sea level. In this problem, we've been asked by the height above sea level that makes the weight of an object 0.30% more lighter.
In accord with the formula
the "normal" or "standard" weight of an object is given by
when
, so we need to find the value of
that makes
meaning that the original weight decrease by a 0.30%, so now we operate...
now we group like terms on the same sides
we cancel equal tems on both sides and obtain that 
The current IDS is greater than 0 since the VGS has induced an inversion layer and the transistor is operating in the saturation region.
<u>Explanation:</u>
- Since
>
because
> Vt. - By the saturation region the MOSFET is operating.
- A specific source voltage and gate of NMOS, the voltage get drained during the specific level, the drain voltage is rises beyond where there is no effect of current during saturated region.
- MOSFET is a transistor which is a device of semiconductor vastly used for the electronic amplifying signals and switching in the devices of electronics.
- The core of this is integrated circuit.
- It is fabricated and designed in an individual chips due to tiny sizes.
Answer:
Explanation:
The VC-T engine (for "variable compression, turbocharged") can adjust its compression ratio between 8:1 and 14:1 on the fly, offering high-compression efficiency under light loads and the low compression needed for turbocharged power under hard acceleration.
Answer:
The mechanical gauge would be the one for the job
Explanation:
Explanation:
I'm not exactly a master at coding, but I'm pretty sure that:
The farmer will remove dirt as long as there is a pile, then stop when the pile is done.