Answer:
Work done by the fluid in the piston=164.5kJ/kg
Specific gas constant= 0.263 kJ/kg K
Molecular weight of gas= 31.54 kmol
A problem that will be handled by a procedure is described by an input-output specification.
<h3>What is input and output specification?</h3>
- An input-output specification outlines the issue that a procedure will try to solve. The input part and the output part are its two components.
- The input component outlines the kind of data object that should be provided for each actual argument as well as any presumptions that the process might make.
- A technical specification known as an output specification defines the project scope primarily through performance-based requirements.
- It is used to assess technical compliance and serves as the technical cornerstone of both the procurement and delivery phases.
- Known as classical specifications, they outline the precise services to be provided, sometimes in great detail, along with the standard you must meet and the approach you must take to meet the standard.
To Learn more About input-output specification Refer To:
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Answer:
1.Economists divide the factors of production into four categories: land, labor, capital, and entrepreneurship. The first factor of production is land, but this includes any natural resource used to produce goods and services.
2.Management skills can be defined as certain attributes or abilities that an executive should possess in order to fulfill specific tasks in an organization. They include the capacity to perform executive duties in an organization. ... and practical experience as a manager. 3.No corrective action is required when the deviations are within acceptable limits. However, when the deviations go beyond the acceptable range, in the important areas, it demands immediate managerial attention so that deviations do not occur again and standards are accomplished.
Answer:
Here are some cool ideas that you could do
-Zero fuel aircraft
-Advanced Space Propulsion Technologies
-Smart Automation and Blockchain
These are some things I've been working on for a few years lol, maybe you will have more luck
Answer:
5984.67N
Explanation:
A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28 psi and a pressure drop of 2 psi occurs through the contraction if the upstream velocity is 4.0 ft/sec. What is the magnitude of the resultant force (lbs) needed to hold the pipe in place?
from continuity equation
v1A1=v2A2
equation of continuity
v1=4ft /s=1.21m/s
d1=14 inch=.35m
d2=14-2=0.304m
A1=pi*d^2/4
0.096m^2
a2=0.0706m^2
from continuity once again
1.21*0.096=v2(0.07)
v2=1.65
force on the pipe
(p1A1- p2A2) + m(v2 – v1)
from bernoulli
p1 + ρv1^2/2 = p2 + ρv2^2/2
difference in pressure or pressure drop
p1-p2=2psi
13.789N/m^2=rho(1.65^2-1.21^2)/2
rho=21.91kg/m^3
since the pipe is cylindrical
pressure is egh
13.789=21.91*9.81*h
length of the pipe is
0.064m
AH=volume of the pipe(area *h)
the mass =rho*A*H
0.064*0.07*21.91
m=0.098kg
(193053*0.096- 179263.6* 0.07) + 0.098(1.65 – 1.21)
force =5984.67N
