Answer:
I do i do it everyday
Explanation:
Press windows and prt sc at the same time
The C++ code that would draw all the iterations in the selection sort process on the array is given below:
<h3>C++ Code</h3>
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, temp1, temp2;
int string2[16] = { 0, 4, 2, 5, 1, 5, 6, 2, 6, 89, 21, 32, 31, 5, 32, 12 };
_Bool check = 1;
while (check) {
temp1 = string2[i];
temp2 = string2[i + 1];
if (temp1 < temp2) {
string2[i + 1] = temp1;
string2[i] = temp2;
i = 0;
} else {
i++;
if (i = 15) {
check = !check;
}
}
}
return 0;
}
Read more about C++ programming here:
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The professional ethics for computer engineers are:
- They will Contribute to society and to human well-being.
- They will Avoid harm.
- Be honest and trustworthy.
- They will be fair and take action that do to discriminate others.
<h3>What are the Characteristics of Code of Ethics?</h3>
The code of ethics are known to be a kind of a universal moral values, that is one that state that what a person expect of any given employee such as been trustworthy, respectful, responsible, and others.
Note that Rules of Practice, Professional Obligations and Codes of Ethics. are known to be put in place to avoid issues that may lead to conflict.
Therefore, i believe that As Engineering and Computing students, the respective professional bodies, Rules of Practice, Professional Obligations and Codes of Ethics are good and acts as a check and balance to us.
Therefore, The professional ethics for computer engineers are:
- They will Contribute to society and to human well-being.
- They will Avoid harm.
- Be honest and trustworthy.
- They will be fair and take action that do to discriminate others.
Learn more about Engineering rules from
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Answer:
7 available
Explanation:
Since 3 colors are available r = 3
Total combination = 35
nCr = 35 ---1
nCr = n!/(n-r)!r!---2
We put equation 1 and 2 together
n-1)(n-2)(n-3)!/n-3)! = 35x 3!
We cancel out (n-3)!
(n-1)(n-2) = 210
7x6x5 = 210
nC3 = 35
7C3 = 35
So If there are 35 combinations, 7 colors are available.
Thank you!
