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umka2103 [35]
3 years ago
7

Simplify the expression 6x + 2x =

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

8 to the 2 power  8

 

Step-by-step explanation:

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Step-by-step explanation:

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Please help |x+10| , if x=−12
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Step-by-step explanation:

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3 years ago
Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
RideAnS [48]

Answer:

V=5.333cubit unit

Step-by-step explanation:

this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1

The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z

The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below

V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:

5 0
3 years ago
What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x
Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the  slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

y-y_1=m\left(x-x_1\right)

substituting the values m = 1/6 and the point (6, -2)

y-\left(-2\right)=\frac{1}{6}\left(x-6\right)

y+2=\frac{1}{6}\left(x-6\right)

subtract 2 from both sides

y+2-2=\frac{1}{6}\left(x-6\right)-2

y=\frac{1}{6}x-3

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

  • y=\frac{1}{6}x-3
5 0
2 years ago
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