Question

In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg m2/s2) and the speed of light = 3.00 × 10^8 m/s ]
Answer

7.2 x 1032 kg

2.7 x 108 kg

9.0 x 10-1 kg

7.2 x 10-16 kg

Answer 1

Use the formula E=mc^2
energy given=8.1 x 10^16 joules
speed of light = 3.00 × 10^8 m/s

plug in the values we'll get mass=9.0 x 10-1 kg

Answer 2

Answer : The mass lost in this reaction will be, $9.0\times 10^{-1}Kg$

Explanation :

According to the Einstein equation, the energy is equal to the product of mass and the square of the speed of light.

The mathematical expression is :

$E=m\times c^2$

where,

E = energy  released = $8.1\times 10^{16}J$

c = speed of light = $3\times 10^8m/s$

m = mass lost = ?

Now put all the given values in the above formula, we get the mass lost in the reaction.

$8.1\times 10^{16}J=m\times (3\times 10^8m/s)^2$

$8.1\times 10^{16}Kg.m^2/s^2=m\times (3\times 10^8m/s)^2$

$m=9.0\times 10^{-1}Kg$

Therefore, the mass lost in this reaction will be, $9.0\times 10^{-1}Kg$