Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
Natural numbers , whole numbers, Integers
The correct answer is the 5th option (one before the last one).
Answer:
Step-by-step explanation:
420 = 1/4 so 4/4 is 4 420s
420 x 4 = 1680
The Pythagorean theorem tells you
... a² + b² = c²
so
... a² = c² - b² = 16² - 9² = 256-81 = 175
... a = √175 = √(25·7)
... a = 5√7
