What you have so far is correct.
Problem 7 is a function because none of the x values repeat. Each x input goes to exactly one y output. The y values can repeat. If the y values repeat, then we don't have a one-to-one function.
In contrast, problem 8 is not a function. We have x = 1 go to y = 8 and y = 6 at the same time. This is one example showing we don't have one output for a given input.
y = -2x + 9
y = 4x - 3
y is isolated in both equations, thus you may set the expressions (-2x + 9) and (4x - 3) equal to each other and solve for x.
-2x + 9 = 4x - 3
Subtract 9 from both sides.
-2x + 9 - 9 = 4x - 3 - 9
-2x = 4x - 12
Subtract 4x from both sides.
-2x - 4x = 4x - 12 - 4x
-6x = -12
Divide both sides by -6.
-6x/-6 = -12/-6
x = 2
Substitute 2 for x into one of the original equations to find y.
y = 4x - 3 (given)
y = 4(2) - 3 (substitute)
y = 8 - 3 (multiply)
y = 5 (subtract)
Plug x- and y-values into original equations to check work.
5 = -2(2) + 9
5 = - 4 + 9
5 = 5
5 = 4(2) - 3
5 = 8 - 3
5 = 5
Answer:
x = 2 and y = 5; (2, 5).
Answer:
6m
Step-by-step explanation:
You can use pretend the shape is a whole parallelogram, then divide it, you can only do this when you have a right angle, however. Or you can use a triangle area formula calculator.
4*3 :2
=4*3= 12
= :2
=6m
. Given that the slope<span> of a </span>line<span> is </span>3<span> and the </span>line passes through<span> the point (-2,</span>4<span>)</span>
