Molar mass KBr = 119 g/mol
Volume in liters: 250.0mL / 1000 => 0.25 L
n = M x V
n = 1.20 x 0,25 => 0.3 moles of KBr
Therefore:
1 mole KBr ----------- 119 g
0.3 moles KBr -------- ??
0.3 x 119 / 1 => 35.7 g of KBr
<span>Who can help me with a few chemistry balancing equations?
Me. Just show me the equations :)</span>
Answer:
calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.
1 mol contains 310 grams
2.3*10^-4 moles contain 2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.
If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.