Answer:
loses electrons and loses potential energy.
Explanation:
A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.
Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.
Answer:
Oxidation can be defined in many ways:
In terms of electron, <em>Oxidation</em> can be defined as loss of electrons by an atom or ion or a molecule during a reaction.
In terms of oxygen transfer, <em>oxidation</em> maybe defined as a substance that gains oxygen or loses hydrogen.
It can also be defined as a process in which a carbon atom gains bond to more electronegative atom such as oxygen.
The speed that they travel
Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and
respectively.
Explanation :
Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).
As we are given that:

Fuel value = 
Molar mass of pentane = 72 g/mol
Fuel value = 
Fuel value = 49.09 kJ/g
Now we have to calculate the fuel density of pentane.
Fuel density = Fuel value × Density
Fuel density = (49.09 kJ/g) × (0.626g/mL)
Fuel density = 30.73 kJ/mL = 
Thus, the fuel density of pentane is 
Answer:
What is the formula for a compound that contains 64.75 g nitrogen and 185.25 g oxygen? D. N2O5
The name of a hydrate is calcium chloride dihydrate. What is its formula? B. CaCl2 x 2H20
Explanation:
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