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Andrei [34K]
3 years ago
9

Which is a true statement about 10 days of production?

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0
B. None of these plants is yet producing actual widgets

Explanation: since number of days is on the x axis, 10 days corresponds to 10 on the x axis. At 10, none of the lines are above 0 on the y axis yet. Since the y axis represents number of widgets, this means none of the plants have produced more than 0 widgets yet.
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Which expressions are equivalent to 70 × 5.3
marin [14]

Answer:

35 x 10.6, 140 x 2.65 and 371 x 1

Step-by-step explanation:


7 0
4 years ago
A manufacturing company uses two different machines, A and B, each of which produces a certain item part. The number of defectiv
damaskus [11]

Answer:A-The mean is 0 and the distribution is approximately normal.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me please​
krok68 [10]

Answer:

y=1

10/5=2

Step-by-step explanation:

7 0
3 years ago
Plz help out with this!!!!
liberstina [14]
1. 6 times 6 = 36 cm
2. 9 times 11 = 99 yd

3. 1/2(13)(8+3)
6.5(11)
71.5 ft

4. 12 times 4 = 48 m
5. 5 times 3 = 15 in
6. 8 times 4 = 32 mm

7. 1/2(8)(10+2)
4(12)
48 yd

8. 4 times 4 = 16 cm
9. 12 times 15 = 180 in
4 0
3 years ago
A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad
faltersainse [42]

Answer:

\text{Length of median AD}=\sqrt{37}

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

D is mid point of BC because median bisect the opposite side of triangle.

Using the formula of mid point. we get coodrinate of D

\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )

D is mid point of B(1,5) and C(-3,-1)

\therefore D \left ( \frac{1-3}{2},\frac{5-1}{2} \right )\Rightarrow (-1,2)

AD is median of triangle ABC. Now we find length of median AD using distance formula of two coordinate.

\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(5,1) and D(-1,2)

AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}

\text{Length of median AD}=\sqrt{37}

Thus, \text{Length of median AD}=\sqrt{37}

8 0
3 years ago
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