Answer:
Self value and rational thinking.
Explanation:
If you don't want to fall in love with someone, list reasons as to why. Understand you're amazing and that you don't <em>need</em> to be with anyone. Self value is very important so you don't fall for people that you believe will support you better than you can.
Good luck! :]
Answer:
Ok
The Limiting reagent is Aluminum. Its not in excess. So the reaction ends once its exhausted. So all Aluminum will be used up
From the question ....
157g of Al
Find the number if reacting Moles...
M=mass/molar mass
M= 157/27
=5.81moles of Aluminum is reacting.
Now looking at the equation of reaction(Always make sure its balanced)...
2moles of Al react to produce 2 Moles of AlCl3
Their Mole ratio is equal
Since their Mole ratio is equal 2:2.... That means... That 5.81moles of AlCl3 would be produced because the mole of Al is 5.81
So We now know the Moles of AlCL3 produced
getting the Mass won't be difficult.
Again
Mole=Mass/Mm
Mass = Mole x Mm(Molar Mass)
Mass of AlCl3 = 5.81 x (27 + 35.5x3)
Note: The arithmetic done in the parenthesis is the molar mass of AlCl3
Mass of AlCl3 = 5.81 x 133.5
=775.63g of AlCl3.
Have a great Day!!!!
I think the answer is: D) The reaction could spend more time in the reverse direction than in the forward direction.
From the information provided in the question, the mass of gold that can be obtained from this sample is 31.5 g of Au.
Given that the reduction of gold III occurs thus;
Au^3+(aq) + 3e ------> Au(s)
Number of moles of gold(III) chloride dihydrate = mass/molar mass = 54.9 g /339.35 g/mol = 0.16 moles
Number of moles of Au^3+ in AuCl3.2H20 = 0.16 moles
Now;
1 mole of Au has a mass of 197 g/mol
0.16 moles of Au has a mass of 0.16 moles × 197 g/mol/1 mole
= 31.5 g of Au.
The mass of gold that can be obtained from this sample is 31.5 g of Au.
Learn more: brainly.com/question/6284546