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2 years ago

A student made the Lewis dot diagram of a compound as shown.

Chemistry

2 answers:

Svetradugi [14.3K]2 years ago

4 0

Answer:

Both electrons of Mg should be transferred to one O.

Explanation:

This is because metals like to lose electrons whereas non metals like to gain electrons in an ionic compound. MgO is an ionic compounds. So Magnesium being a metal in group 2 of periodic table, it wants to donate 2 electrons to get to the octet rule, so it donates its electrons and oxygen accepts them to fill its octet rule.

Kazeer [188]2 years ago

3 0

Answer B

Mg has a positive ionic charge because it hoped to loose its two electrons to make it stable or happy

O had a negative ionic charge bc it wants to gain electrons to make it stable or happy

therefore,

QA) O would not want/wouldn't use up the energy to transfer 6 of its electrons and Mg would accept O's electrons
Q3) goes against laws of chemistry
Q4) Mg can not gain 2 extra electrons unless it is a double molecule (which it is not) a

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The majority of the mass of the atom is located in the _______. A) nucleus B) core electrons C) pions and quarks D) valence elec

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The majority of the mass of the atom is located in the nucleus. Remember that the nucleus contains both protons and neutrons and therefore, most of the mass of the atom.

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2 years ago

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What products will form when potassium is added to cold, liquid water?

rewona [7]

Answer:

Explanation:

Potassium metal reacts very rapidly with water, which forms Potassium hydroxide (KOH) and hydrogen gas (H2).

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3 years ago

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What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?

Rus_ich [418]

If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component = $\frac{number of moles of component}{total number of moles of all components }$
number of moles of ethanol - 3.00 mol
total number of moles in mixture - 3.00 + 5.00 = 8.00 mol

mole fraction of ethanol = $\frac{3.00 mol}{8.00 mol }$
mole fraction of ethanol is 0.375

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3 years ago

El pH de una solución acuosa 10^-14 M de ácido acético, a 25°C, es igual a, teniendo en cuenta que Ke = 1.76x10^-5

frez [133]

Answer:

$pH=14$

Explanation:

Hola!

En este caso, consideramos que la disociación de ácido acético ocurre:

$CH_3COOH\rightarrow CH_3COO^-+H^+$

Así, mediante la solución del equilibrio ácido, podemos calcular la concentración de iones hidronio que posteriormente sirven para calcular el pH de la solución, por tal razón, debemos calcular el equilibrio dada la constante de equilibrio y por medio de la ley de acción de masas en términos del cambio $x$ como cualquier problema de equilibrio:

$Ke=\frac{CH_3COO^-][H^+]}{[CH_3COOH]}\\\\1.76x10^{-5}=\frac{x*x}{1x10^{-14}M-x}$

Resolviendo para $x$ , tenemos $x=0.999x10^{-14}$

Así, la concentración de hidrógeno es igual a x, por lo que el pH:

$pH=-log([H^+])=-log(0.999x10^{-14})\\\\pH=14$

Dicho valor tiene sentido desde que la concentración de hidrógeno es casi despreciable, por lo que se puede asumir que tiende a ser básica.

Saludos!

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3 years ago

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A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point

Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution ( $\frac{moles}{liters}$ ) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

$moles = \frac{.410 moles}{L} *.02L$

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

$HCl + NaOH = NaCl + H_{2} O$

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

$\frac{.0082mol}{.320mol/L}$

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

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2 years ago