Answer:
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
Explanation:
<u>Step 1:</u> Data given
Wine 1 has a pH of 3.5
Wine 2 has a pH of 2.9
Wine 2 is more acid so should have more hydrogen ions
<u>Step 2:</u> Calculate hydrogen concentration
pH = -log [H+]
Wine 1: pH = 3.5 = -log[H+]
[H] = 10 ^-3.5 M = 0.00032 M
Wine 2: pH =2.9 = -log[H+]
[H+] = 10^-2.9 = 0.00126 M
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
The italian white wine has a higher concentration of hydrogen ions, what means it's more acid than the californian red wine.
Answer: NaCl; Sodium Chloride
Explanation:
First of all what the heck to the other guy that answered. And the correct answer is FALSE :))
Answer:
18.76 g of copper II nitrate
Explanation:
Now recall that we must use the formula;
n= CV
Where;
n= number of moles of copper II nitrate solid
C= concentration of copper II nitrate solution
V= volume of copper II nitrate solution
Note that;
n= m/M
Where;
m= mass of solid copper II nitrate
M= molar mass of copper II nitrate
Thus;
m/M= CV
C= 0.05 M
V= 2.00 L
M= 187.56 g/mol
m= the unknown
Substituting values;
m/ 187.56 g/mol = 0.05 M × 2.00 L
m= 0.05 M × 2.00 L × 187.56 g/mol
m= 18.76 g of copper II nitrate
Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.
Answer:
Because we need to dispense 4.7 mL, the volume reading in the pipet is the 5.3 mL line.
Explanation:
First we use C₁V₁=C₂V₂ in order to <u>calculate the required volume of concentrated HCl</u> (V₁):
12.85 M * V₁ = 0.600 M * 100 mL
V₁ = 4.7 mL
<u>So we need to dispense 4.7 mL of the concentrated HCl solution</u>. The mark in the pipet that would contain that volume would be 10.0 - 4.7 = 5.3 mL
