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4 years ago

15

Why is it important to have a controlled experiment

2 answers:

Ivanshal [37]4 years ago

6 0

It is important to have a control group in your experiment so you are able to compare your actual results to the control group

Alexus [3.1K]4 years ago

3 0

By the end of the day you know how much each group ate, abd you compare it with the control.In convlution,control is important because without it you'd have no way to understand the results after and experiment happens.

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The specific heat of gasoline is 2.22 J/g•°C. How much heat would it take to raise 35.0 G of gasoline to 3.00°C?

Olenka [21]

<span>To find the amount of heat energy required to raise a substance by a certain number of degrees, we simply multiply: (specific heat * change in temperature * mass) Heat = 2.22 * 35 * 3 = 233.1 joules Therefore, we would need 233.1 joules of heat to raise the temperature by 3 degrees Celsius.</span>

3 0

4 years ago

Examples of non polar covalent bonds

ikadub [295]

Answer:

# The simpliest is: H-H

# All gases formed by elements of the 7th group in the periodic table:

F-F, Cl-Cl, Br-Br, I-I

# In general, Covalent bonds formed between atoms of the same kind are usually non-polar.

Explanation:

Hope this answer will help you.

4 0

3 years ago

Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)????c=9.40 at 900 K Ho

Maru [420]

Answer : The mass of $CS_2$ is, 555.028 grams

Explanation :

First er have to calculate the concentration of $S_2$ .

$\text{Concentration of }S_2=\frac{\text{Moles of }S_2}{\text{Volume of solution}}=\frac{8.08mole}{5.35L}=1.51mole/L$

Now we have to calculate the concentration of $CS_2$ .

The given balanced chemical reaction is,

$S_2(g)+C(s)\rightleftharpoons CS_2(g)$

Initial conc. 1.51 0 0

At eqm. conc. (1.51-x) (x) (x)

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CS_2]}{[S_2]}$

Now put all the given values in this expression, we get :

$9.40=\frac{x}{(1.51-x)}$

By solving the term 'x', we get :

x = 1.365 M

Concentration of $CS_2$ = x M = 1.365 M

Now we have to calculate the moles of $CS_2$ .

$\text{Moles of }CS_2=\text{Concentration of }CS_2}\times \text{Volume of solution}=1.365mole/L\times 5.35L=7.303mole$

Now we have to calculate the mass of $CS_2$ .

Molar mass of $CS_2$ = 76 g/mole

$\text{Mass of }CS_2=\text{Moles of }CS_2}\times \text{molar mass of }CS_2}=7.303mole\times 76g/mole=555.028g$

Therefore, the mass of $CS_2$ is, 555.028 grams

3 0

4 years ago

For a half-reaction in an acidic solution, which substances should you add to balance the equation?

Murljashka [212]

The answer to this question is A

7 0

3 years ago

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What are the content of water in molecules

Molodets [167]

Answer:

A water molecule is made up of two hydrogen atoms and one oxygen atom.

Explanation:

5 0

3 years ago

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