<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate?
</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
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F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
Answer: The correct answer is- Field.
Explanation -
The modified space around a charged particle is known as electric field.
The strength of electric field at a point is calculated as the force experienced by a unit test charge present at that point.
Thus, a region of space in which a test charge experiences a force is referred to as Field.
Vi = 2m/s
a= 4.5 m/s
d= 340 m
vf= ?
use this equation ... vf^2=vi<span>^2+2ad
you should get vf = 55.3
hope this helps </span>
Explanation:
Liquids also exert pressure in all directions on the walls of the container they are stored in. We see water coming out from leaking pipes and taps. ... Gases (Air) also exert pressure in all directions
