Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=
Temperature=T=
Pressure at sea level = P= 1 atm=
R is universal Gas Constant =8.314 J/mol.K
Formula:
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
The radius of the loop is 18.9 km
Explanation:
When the airplane is at the top of the loop, the pilot experiences two forces:
Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:
where
m is the mass of the pilot
is the acceleration of gravity
N is the normal reaction
v = 430 m/s is the speed of the plane
r is the radius of the loop
Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,
N = 0
Therefore the equation becomes
And so we can find the radius of the loop:
Learn more about circular motion:
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