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Fynjy0 [20]
3 years ago
5

In this formula, g=GM/R^2 , what do G ,m and R stand for?​

Physics
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

Explanation:

g means gravitation

G is universal gravitational constant

M = mass of the earth

R = radius of the earth

Hope this helps

plz mark as brainliets!!!!!!!!!

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Which of the following mechanical waves has the most energy?
zhenek [66]
Gamma radiation has the greatest energy<span>. This </span>is<span> because gamma radiation </span>has the highest <span>frequency. </span>Energy<span> a frequency.

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3 years ago
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
frez [133]

Answer:

<em>1.49 x </em>10^{11}<em></em>

<em></em>

Explanation:

Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>

Mathematically, this can be stated as

T^{2} ∝ R^{3}

<em>to remove the proportionality sign we introduce a constant</em>

T^{2} = kR^{3}

k = \frac{T^{2} }{R^{3} }

Where T is the orbital period,

and R is the orbit around the sun.

For mars,

T = 687 days

R = 2.279 x 10^{11}

for mars, constant k will be

k = \frac{687^{2} }{(2.279*10^{11}) ^{3} } = 3.987 x 10^{-29}

For Earth, orbital period T is 365 days, therefore

365^{2} = 3.987 x 10^{-29} x R^{3}

R^{3} = 3.34 x 10^{33}

R =<em> 1.49 x </em>10^{11}<em></em>

8 0
3 years ago
Read 2 more answers
A theory is a way of explaining observations. true or false.
Natasha_Volkova [10]
I think its true. hope this helps.
5 0
3 years ago
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A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ
ra1l [238]

Answer:

The correct question is:

"Find the energy each gains"

The energy gained by a charged particle accelerated through a potential difference is given by

\Delta U = q\Delta V

where

q is the charge of the particle

\Delta V is the potential difference

For a proton,

q=+e=1.6\cdot 10^{-19}C

And since \Delta V=100 V

The energy gained by the proton is

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

For an alpha particle,

q=+2e=3.2\cdot 10^{-19}C

Therefore, the energy gained is

\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

q=+e=1.6\cdot 10^{-19}C

So the energy gained is the same as the proton:

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

6 0
3 years ago
Forces that are opposite and equal are
Kisachek [45]

Answer:

space

Explanation:

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