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blagie [28]
3 years ago
5

A circle has a radius of \sqrt{45} 45 ​ square root of, 45, end square root units and is centered at (-2.4,-4.8)(−2.4,−4.8)(, mi

nus, 2, point, 4, comma, minus, 4, point, 8, ). Write the equation of this circle.
Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

Answer:

x^2+y^2+4.8x+9.6y-16.2=0

Step-by-step explanation:

The equation of a circle centre(h,k) of radius r is given by:

r²=(x-h)²+(y-k)²

If radius, r=\sqrt{45}

Centre, (h,k)=(-2.4,-4.8)

Substitution into the equation of the circle formula

r²=(x-h)²+(y-k)²

(\sqrt{45})^{2}=(x-(-2.4))^{2}+(y-(-4.8))^{2}

45=(x+2.4)^{2}+(y+4.8)^{2}

45=x^2+4.8x+5.76+y^2+9.6y+23.04

0=x^2+y^2+4.8x+9.6y+5.76+23.04-45

x^2+y^2+4.8x+9.6y-16.2=0

The equation of the circle is therefore given as:

x^2+y^2+4.8x+9.6y-16.2=0

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