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3 years ago

how so you solve 5x+27=9(x+3)-4x and is this a conditional equation, an identity, or an inconsistent equation

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

To solve this, follow these steps:

5x + 27 = 9 (x+3) - 4x

Distribute the 9 within the parenthesis:

5x + 27 = 9x + 27 - 4x

Then combine like terms:

5x + 27 = 5x + 27

These two then cancel each other out completely.

This is an identity because an identity in math is when both equations equal each other, which is shown above.

Hope this helps!

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3 years ago

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2 years ago

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Answer:

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3 years ago

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eimsori [14]

Answer : The expression which is equivalent to $\sqrt[4]{9}^{\frac{1}{2}x}$ is $9^{(\frac{1}{8}x)}$ .

Step-by-step explanation :

The given expression is:

$\sqrt[4]{9}^{\frac{1}{2}x}$

As we know that:

$\sqrt[4]{x} =x^{\frac{1}{4}}$

So, by solving the above expression, we get:

$\Rightarrow 9^{(\frac{1}{4}\times \frac{1}{2}x)}$

By multiplying the power of 9, we get the following expression.

$\Rightarrow 9^{(\frac{1}{8}x)}$

Hence, the expression which is equivalent to $\sqrt[4]{9}^{\frac{1}{2}x}$ is $9^{(\frac{1}{8}x)}$ .

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3 years ago