All categories

3 years ago

Given ED, DB which statements about the figure are true? Check all that apply.

Mathematics

1 answer:

Klio2033 [76]3 years ago

6 0

Answer: EB is bisected by DF

A is the midpoint DF

EB is a segment bisector

FA=1/2FC.

Step-by-step explanation:

You might be interested in

PLEASEEEEEEE HELPPPPPP

Zinaida [17]

Answer:

bajajakakakakkakakskakallalalalalallakakakaka

Step-by-step explanation:

hey ypuuuuuuuuuuuuuuuuuuuuu is opción a hajajakskamqmsjkwkqkqkqkwnanannanaan

8 0

3 years ago

SOLVE <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B-4%7D" id="TexFormula1" title="\frac{12}{-4}" alt="\frac{12}{-4}"

ivanzaharov [21]

Answer: 12/-4= -3. -12/4=-3. -(12/4)= -3

Step-by-step explanation: All equal -3 just divide all of them to get the answer.

7 0

3 years ago

Read 2 more answers

PLEASE HELP!!

aev [14]

Answer:

D. No, because $P(A|B)=0.22$ and the $P(A) = 0.53$ are not equal.

Step-by-step explanation:

Given:

Probability of doing yard work is, $P(A)=53\%=0.53$

Probability of raining, $P(B)=68\%=0.68$

Probability of doing yard work and it raining is, $P(A\cap B)=15\%=0.15$

Now, two events A and B are independent if,

$P(A|B)=P(A);P(B|A)=P(B)$

Conditional probability of event A given that B has occurred is given as:

$P(A|B)=\frac{P(A\cap B}{P(B)}\\P(A|B)=\frac{0.15}{0.68}=0.22$

So, $P(A|B)=0.22\ and\ P(A)=0.53$

Since, $P(A|B)\ne P(A)$ , A and B are not independent events.

8 0

3 years ago

. Compute the required sample size given the required confidence in the sample results is 99.74% (Z score of 3). The level of al

Shtirlitz [24]

Answer:

900 sample size

Step-by-step explanation:

To determine the sample size for a proportion, the margin of error formula is used to determine this:

$E=Z_{\frac{\alpha}{2} }*\sqrt{\frac{\hat p \hat q}{{n} }$

$n=\hat p \hat q*(\frac{Z_{\frac{\alpha}{2} }}{E} )^2$

Where p is the proportion, E is the margin of error, n is the sample size, q = 1 - p, $Z_\frac{\alpha }{2}$ is the z score.

Since the proportion is not known, the sample size needed to guarantee the confidence interval and error is at p = 0.5 and q = 1 - p = 1 - 0.5 = 0.5

E = 5% = 0.05, $Z_\frac{\alpha }{2}$ = 3. Hence:

$n=0.5*0.5*(\frac{3}{0.05} )^2\\\\n = 900$

6 0

3 years ago

Find the system determinant of the given matrix.<br><br>FAST please.

cricket20 [7]

Answer:

the answer is -30

Step-by-step explanation:

| 2 4 |

| 3 -9| = ( 2 * (-9) ) - ( 4 * 3)

= - 18 - 12

= -30

7 0

3 years ago