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abruzzese [7]
4 years ago
8

Mind if I get some assistance?

Mathematics
1 answer:
lora16 [44]4 years ago
3 0
Appositive is a noun that renames another noun right beside it. So the appositive phrase in this sentence is "my classmate".
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____________________
MaRussiya [10]

Step-by-step explanation:

the numbers of the yellow and white counters

= 288- 38 = 250.

the ratio of yellow to white = 1:4

so,

the numbers of the yellow counters =

1/(1+4) × 250 =1/5 ×250 = 50

the numbers of the white counters =

4/(1+4) ×250 = 4/5 ×250 = 200

and the numbers of the red counters = 38

7 0
3 years ago
Y/x^2 + y/x^3<br><br>perform the operation and express your answer as a single fraction​
umka2103 [35]

Answer:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

Step-by-step explanation:

Given the expression

\frac{y}{x^2}+\frac{y}{x^3}

Let us perform the operation and express your answer as a single fraction​

\frac{y}{x^2}+\frac{y}{x^3}=\frac{x^3y+x^2y}{x^5}

            =\:\frac{x^2\left(xy+y\right)}{x^5}

            =\frac{\left(xy+y\right)}{x^3}

Therefore, we conclude that:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

3 0
3 years ago
Please help me factorize this<br>x(a-<br><img src="https://tex.z-dn.net/?f=x%28a%20-b%29%20%2B%20a%20-%20b" id="TexFormula1" tit
Nostrana [21]
I’m not sure but I think it’s:
(a-b)(x+1)
7 0
3 years ago
(-4)(5)+(-3)(-2) whats is it???
Vlada [557]

Answer:

-14

Step-by-step explanation:

(-4)(5)+(-3)(-2)

=-20+6

=-14

5 0
4 years ago
Read 2 more answers
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
3 years ago
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