Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.
Using:
F = ma
a = 8.2 / 5
a = 1.64 N/kg
The gravitational field strength is equivalent to 1.64 N/kg.
Answer:
Distance= 3.5/31536000 cm = 1.11 × 10^(-7) cm
Explanation:
Given ;
Average speed = 3.5cm/year
Time= 1 s
Distance = speed × time
Number of seconds in a year = 31536000 sec/year
Distance = 3.5 cm/year × 1/31536000sec/year × 1 s
Distance= 3.5/31536000 cm = 1.11 × 10^(-7) cm
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Answer:
The size of the electric current is 154.74 A.
Explanation:
It is assumed that,
Charge, q = 93 C
Time,
We need to find the size of the electric current. It is equal to the electric charge per unit time. It is given by :
I = 154.74 A
So, the size of the electric current is 154.74 A. Hence, this is the required solution.