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liq [111]
3 years ago
8

Help Please I'm taking my finals review

Mathematics
1 answer:
lesantik [10]3 years ago
4 0
If b=2 and c=3,  then
a= √(3²-2²) = √(9-4) = √5

If a=3 and c=6,  then
b= √(6²-2²) = √(36-9) = √27 = 3√3

If a=4 and b=6,  then
c= √(4²+6²) = √(16+36) = √52 = 2√13
You might be interested in
Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea
Ulleksa [173]

Answer:

63 degrees

Step-by-step explanation:

add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.

3 0
4 years ago
Three friends went apple picking and then counted the apples they picked.Who had the largest red to green apple ratio? Use compl
antoniya [11.8K]

Answer:

Carmen had the largest red to green apple ratio of 5 : 3

Step-by-step explanation:

Red apples : Green apples

Carmen = 20 red apples : 12 green apples

= 20 / 12

= 5 / 3 = 1.67

= 5 : 3

Dylan = 12 red apples : 10 green apples

= 12 / 10

= 6 / 5 = 1.2

= 6 : 5

Eli = 16 red apples : 20 green apples

= 16 / 20

= 4 / 5 = 0.8

= 4 : 5

Carmen had the largest red to green apple ratio of 5 : 3

7 0
3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
draw3 rows with 2 counters in each row write a word problem that can be acted out using these counters
Gnoma [55]
Pretend * is counter

*   *   *
*   *   *

the word problem could be in a box of chocolates there is 3 rows and 2 chocolates in each row how many chocolates are there total.
6 0
3 years ago
Read 2 more answers
Please help me !!!
Pie
3. 5mn ( 2m + 6n + 1 )
4. 4a^3b^2c ( 18a^2b - 8c )
5. (X-15)(X+15)
6. -4(y-4.5)(y+4.5)
8. 2X(X-10)(X+10)
i am not sure if no. 8 is right
8 0
4 years ago
Read 2 more answers
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