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statuscvo [17]
3 years ago
11

Jack was planting a tree. He was to dig a hole that was 3 feet deep for every 5 feet of tree height. How deep should he dig the

hole for a tree that is 17 feet high?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
I believe it is 10 feet deep.
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Mrs.smith earns $3500 a month. She saves $280 a month. Savings is what percent of her income?
arlik [135]

Answer:

3500 280

Step-by-step explanation:

280/3500

280 divided by 3500 times 100 (type this into a calculator)

its 8 her savings are 8 percent of her income

4 0
3 years ago
What is 0.000 002 in standard form​
Vsevolod [243]

Answer:

0.000 002 = 2 \times  {10}^{ - 6}

Step-by-step explanation:

It is already in standard form and can be expressed in scientific form as:

0.000 002 = 2 \times  {10}^{ - 6}

5 0
3 years ago
Read 2 more answers
X + y = -3 & 5x - 2y = -50 ELIMINATION
Karolina [17]
I gotchu luh bro....

7 0
3 years ago
Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She
andreyandreev [35.5K]

Answer:

3w+45=557

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

w+33 kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

w+12 kg.

The total weight of all boxes is

w+(w+33)+(w+12)=w+w+33+w+12=3w+45 kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

3w+45=557

or

3w=512

3 0
3 years ago
A gym has 200 members who pay $30 per month for unlimited use of the gym’s equipment. A survey of the members indicates that for
Bas_tet [7]
Given:

Current revenue = $6000

<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases

We are told to find f, when R(f) </span><span>< 6000

Since </span>R(f)= -100f^2+400f+6000

R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000


Subtract 6000 from both sides

-100f^2 + 400f + 6000 - 6000 < 6000 - 6000

-100f^2 + 400f < 0

⇒ 400f - 100f^2 < 0


Divide the equation by 100

400f/100 - 100f^2/100 < 0/100

4f - f^2 < 0


Add f^2 to both sides of the equation

4f - f^2 + f^2 < 0 + f^2

4f < f^2


Divide both sides by f

4f/f < (f^2)/f

4 < f

⇒ f > 4

⇒ f ≥ 5

Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
8 0
3 years ago
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