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zmey [24]
3 years ago
13

Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis

Physics
1 answer:
ioda3 years ago
7 0
L=Iw
I_{earth} =  \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}
L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}<span>[/tex]</span>

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Five equal negative charges are uniformly spaced in a semicircular
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Answer:

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Explanation:

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A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns
Eddi Din [679]

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

f'=\frac{V+V_{o}}{V-V_{s}} f  (1)

Where:

f=250,000 Hz is the actual frequency of the sound wave

f'=240,000 Hz is the "observed" frequency

V=340 m/s is the velocity of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which is the balloon

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}  (2)

V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}  (3)

V_{s}=-14.16 m/s (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (t=4.8 s) given as data, we can find the distance:

d=V_{s}t (5)

d=(14.16 m/s)(4.8 s) (6)

Finally:

d=68 m (8) This is the distance of the balloon from the radar station

6 0
3 years ago
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Norma-Jean [14]
Use the kinematic equation: d = vi • t + ½ • a • t^<span>2
</span>
<span>20=0(t)+(0.5)(9.8)(t^2)
</span>20=4.9(t^2)
t=2.02seconds
---------------------------------
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3 years ago
What is the relationship between frequency and wavelength?
mash [69]

Answer:

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Explanation:

none

6 0
3 years ago
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