2 years ago

Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis

1 answer:

ioda2 years ago

7 0

$L=Iw$
$I_{earth} = \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}$
$L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}$ <span>[/tex]</span>

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