Answer:
T = 5163.89 N
Explanation:
Newton's first law:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
We define the x-axis in the direction parallel to the movement of the car on the ramp and the y-axis in the direction perpendicular to it.
Forces acting on the car
W: Weight of the car : In vertical direction
FN : Normal force : perpendicular to the ramp
T :Tension force: at angle of 31.0° above the surface of the ramp
Calculated of the Weight of the car (W)
W = m*g m: mass g:acceleration due to gravity
W = 1130-kg* 9.8 m/s² = 11074 N
x-y weight components
Wx = 11074 N*sin 25.0° = 4680.07 N
Wy = 11074 N*cos 25.0° = 10036.45 N
x-y Tension components
Tx = T*cos 25.0°
Ty = T*sin 25.0°
Newton's first law:
∑Fx =0 Formula (1)
Tx-Wx = 0
T*cos 25.0° - 4680.07 = 0
T*cos 25.0° = 4680.07
T = 4680.07 / cos 25.0°
T = 5163.89 N
Answer:
c neither
Explanation:
the cactus is just kinda chillin there
Answer:
I think 5 km/h but I am not sure
Answer:
The ratio of the orbital time periods of A and B is 
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:
where
R = Radius of the orbit
Now,
For satellite A:
Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):
