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Ira Lisetskai [31]
3 years ago
9

Can a white person call a black dude a negro

Physics
2 answers:
Ludmilka [50]3 years ago
7 0

Answer:

no that would be racist even tho

it’s not saying n***a

NARA [144]3 years ago
5 0
No, because the word might offend that person.
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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

  • m1 = 281kg
  • u1 = 2.82m/s
  • m2 = 209kg
  • u2 = -1.72m/s
  • v1 = ?

Let's substitute the values into the equation.

v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0
2 years ago
Calculate the potential difference if 20J of energy are transferred by 8C of charge.
grin007 [14]
<h2>v = 2.5J/c</h2>

Explanation:

<h2>Given:</h2>

<h3>Energy = E = 20J</h3>

<h3>Charge = Q = 8C</h3>

<h2>Require :</h2>

___________

<h3>Potential Difference = V = ?</h3>

<h2>Formula :</h2>

____________

<h2>V = \frac{E}{Q}</h2>

<h2>Solution:</h2><h3>_________</h3>

<h2>V = \frac{20J}{8C}</h2>

<h3>V = 2.5V</h3>

.

.

.

<h2>\color{Red}{Mark - Brainliest}</h2>
4 0
3 years ago
Eric, Sheena, and Yael are playing a game. Eric has half as many points as Sheena. Sheena has two fewer points than Yael. Togeth
nexus9112 [7]

Lets say that:

Eric is E

Sheena is S

Yael is Y


We know that S+2=Y, E= 1/S and that E+S+Y=52. So, we can insert S+2=Y and E= 1/S into our other equation, which would bring us to (1/2S)+(S+2)+S=52. This is equal to 1/2S+S+2+S=52. We then use algebra to get the answer:

Given:

S+2=Y

E=1/S

E+Y+S=52

Equation:

1/2S+S+2+S=52

1/2S+S+S=52

2.5S=50

S=50/2.5

S=20

And since Yael has 2 more points then Yael then we do 20+2 and get 22.

Hope this helps! <3

6 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 2.4
NeX [460]

When person is observing destructive interference at 0.20 m distance from the equidistant position then we can say that path difference must be equal to half of the wavelength

now we will have

\frac{\lambda}{2} = \frac{yd}{L}

now we know that

y = 0.20 m

d = 2.4 m

L = 10 m

now here we have

\frac{\lambda}{2} = \frac{0.20\times 2.4}{10}

\lambda = 0.096 m

now frequency of wave is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.096} = 3573 Hz

5 0
3 years ago
An optical fiber made of glass with an index of refraction 1.50 is coated with a plastic with index of refraction 1.30. What is
Helen [10]

To solve this problem we will use Snell's law. This law is used to calculate the angle of refraction of light by crossing the separation surface between two means of propagation of light (or any electromagnetic wave) with a different index of refraction.

n_1 sin\theta_1 = n_2 sin\theta_2

Where,

n_{1,2} = Index of refraction for each material

\theta_1= Angle of incidence and refraction

A ray of light propagating in a medium with index of refraction n_1 hitting an angle \theta_1 on the surface of a medium of index n_2 with n_1> n_2 can be fully reflected inside the medium of highest refractive index:

\theta_{critical} = Sin^{-1}(\frac{n_1}{n_2})

n_1 Refractive index of rarer medium

n_2 Refractive index of denser medium

Replacing we have,

\theta_{critical} = Sin^{-1}(\frac{n_1}{n_2})

\theta_{critical} = Sin^{-1}(\frac{1.3}{1.5})

\theta_{critical} = 60.07\°

the critical angle of this fiber at the glass-plastic interface is 60.07°

8 0
3 years ago
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