1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elden [556K]
2 years ago
7

Please help 22 points

Mathematics
2 answers:
uranmaximum [27]2 years ago
6 0
The answer to this equation is 8/15
disa [49]2 years ago
3 0

Answer:

8/15

Step-by-step explanation:

4/5 x 2/3 = 8/15

or

4/5 x 2/3 = 0.5333

hope this helps ^w^

You might be interested in
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
KATRIN_1 [288]

Answer:

I'm 99% sure the answer is A

Step-by-step explanation:

8 0
2 years ago
A car begins to depreciate at a rate of 24.9% annually as soon as it is driven off the lot. If a car was purchased for 26,500; h
STatiana [176]

Answer:

13197

Step-by-step explanation:

You have to do 24.9*2 and then find that percent of 26500

6 0
3 years ago
I don't know how to answer this
scoray [572]
If you have a protractor measure the degrees in vetesis

4 0
3 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
3 years ago
Any1 answer for me? pls
disa [49]
Give me a few secs brb
5 0
2 years ago
Other questions:
  • If measure of angle 3= 74 find each measure
    11·1 answer
  • A3-b3=(a-b)(a2+an+b2) 64x6-27
    12·1 answer
  • Rachel's garden is square in shape. The length of one side of her garden is 52 feet. What is the area of her garden in square fe
    12·1 answer
  • The table shows a direct variation.
    12·1 answer
  • I hope you guys can help me with this question :)
    11·2 answers
  • 45% to a decimal ples help out
    5·2 answers
  • Terry buys an orange for 22p.
    6·1 answer
  • Round to the nearest hundredth
    7·1 answer
  • HUH giving out brainiest
    11·1 answer
  • Which BEST explains the expression x( y z + 1 2 )? A) x depends on ( y z + 1 2 ). B) ( y z + 1 2 ) depends on x. C) x and ( y z
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!