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Elden [556K]
3 years ago
7

Please help 22 points

Mathematics
2 answers:
uranmaximum [27]3 years ago
6 0
The answer to this equation is 8/15
disa [49]3 years ago
3 0

Answer:

8/15

Step-by-step explanation:

4/5 x 2/3 = 8/15

or

4/5 x 2/3 = 0.5333

hope this helps ^w^

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A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh
Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = -0.02x^{2} +0.8x+3

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = -0.02x^{2} +0.8x+3

Y(x) = -0.02(10)^{2} +0.8(10)+3

Y(x) = -0.02(100)} +8+3

Y(x) = -2 +8+3

Y(x) = 9

<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D.  9 ft is correct

6 0
3 years ago
What is the value of 8 in the number 159.82??
sergey [27]

it the tenths I think.....

7 0
3 years ago
Cedric and Insha solved the same equation using the calculations below.
Mariulka [41]

The first working out is correct, z = 3

3 0
3 years ago
Please help me, i promise its worth it!!!
Rashid [163]

\\ \sf\longmapsto 2(L+B)=55

\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55

\\ \sf\longmapsto \dfrac{8}{3}x+2x=55

\\ \sf\longmapsto \dfrac{8x+6x}{3}=55

\\ \sf\longmapsto \dfrac{14x}{3}=55

\\ \sf\longmapsto 14x=165

\\ \sf\longmapsto x=11.78

\\ \sf\longmapsto x\approx 12

Now

  • B=x=12
  • L=4/3(12)=4(4)=16
5 0
2 years ago
Read 2 more answers
Determine the greatest common factor of 28xy^9z and 32x^2y^7z
RSB [31]

Answer:

GCF = 4xy⁷z

Step-by-step explanation:

Do Prime Factorizations for each term and select only those terms common to each:

28xy⁹z = 2·2·7·x·y·y·y·y·y·y·y·y·y·z

32x²y⁷z = 2·2·2·2·2·x·x·y·y·y·y·y·y·y·z

GCF = 2·2·x·y·y·y·y·y·y·y·z

GCF = 4xy⁷z

5 0
2 years ago
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