Assuming the same current is running through two separate coils, why is it easier to thrust a magnet into a wire coil with one l
2 answers:
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Answer:
Explanation:
given
T = 3months = 7.9 × 10⁶s
orbital speed = 88 × 10³m/s
V= 2πr÷T
∴ r = (V×T) ÷ 2π
r = (88km × 7.9 × 10⁶s) ÷ 2π
r = 1.10 × 10⁸km
using kepler's 3rd law
mass of both stars = (seperation diatance)³/(orbital speed)²
M₁ + M₂ = (2r)³/(year)²
= (1.06 × 10²⁵)/(6.2×10¹³)
1.71×10¹²kg
since M₁ = M₂ =1.71×10¹²kg ÷ 2
M₁ = M₂ = 8.55×10¹¹kg
Answer and explanation:
A.
Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)
B.
In muon rest frame it travels Zero meters
C.
Distance, d = Velocity, v * Time, s
D.
Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame
that is same as in part C which is 594m
E.
Using lorentz contraction
In the rest frame of someone standing on the mountain
the distance is given by
d' = 258.92m
F.
in the rest frame of someone standing on the mountain,
muon moves straight down