Question

Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?

Answer 1

Data:

$E = 20 V$
$R_{1} = 65\Omega$
$R_{2} = 65\Omega$
$R_{3} = 65\Omega$
$R_{4} = 65\Omega$

Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

$R_{T} = R_{1} + R_{2} + R_{3} + R_{4}$
$R_{T} = 65 + 65 + 65+ 65$
$R_{T} = 260\Omega$

Like this:

$I_{T} = \frac{E}{ R_{T} }$

$I_{T} = \frac{20}{ 260 }$
$I_{T} = 0,076923076...$

$\boxed{\boxed{I_{T} \approx 0,07A}}$ 
Answer:
The intensity of the total electric current 
$\boxed{\boxed{I_{T} \approx 0,07A}}$ 

P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.