<u>Answer:</u> The correct option is enough solvent to make 1.00 L of solution
<u>Explanation:</u>
A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.......(1)
We are given:
Molarity of solution = 0.500 M
Moles of solute = 0.500 moles
Putting values in equation 1, we get:
Hence, the correct option is enough solvent to make 1.00 L of solution
Answer:
24%
Explanation:
From the question, the limiting reactant is H2S.
The reaction equation is;
2H2S + O2 → 2S + 2H2O
Number of moles of H2S reacted = 22g/34 g/mol = 0.647 moles
According to the reaction equation;
2 moles of H2S yields 2 moles of sulphur
0.647 moles of H2S yields 0.647 moles of sulphur
So;
Theoretical yield of sulphur = 0.647 moles * 32 g/mol = 20.7 g
Actual yield = 5 g
% yield = actual yield/theoretical yield * 100
% yield =5 g/20.7 g * 100
% yield = 24%
Answer:
<em>Well, Your best answer will be is 2H+ + 2OH- -> 2H2O but you have to reduce it to H+ + OH- -> H2O. </em><em>Good Luck!</em>
<h3>
Answer:</h3>
pH = 8.66
<h3>
Explanation:</h3>
- The pH refers to the acidity or alkalinity of a solution.
- It is calculated by getting the negative logarithm of Hydrogen ions concentration.
In this case;
we are given [OH⁻] as 4.6 x 10^-6 M
We are required to calculate the pH
We need to know that;
pH + pOH = 14
pOH = -log[OH⁻]
To get the pH we can calculate the pOH first,
pOH = -log[4.6 x 10^-6 M]
= 5.34
but, pH + pOH = 14
Therefore, pH = 14 - pOH
= 14 - 5.34
= 8.66
Therefore, the pH of the solution is 8.66
Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is, 
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈ 
Therefore, the heat released by the combustion of 1.121 mol of hexane is .
