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3 years ago

Hank and Debra each own two milking cows

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

Is there supposed to be a picture attached?

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Solve the equation.

Vinil7 [7]

If you would like to solve the equation x + 1/6 = 6, you can do this using the following steps:

x + 1/6 = 6 /-1/6
x + 1/6 - 1/6 = 6 - 1/6
x = 6 - 1/6
x = 36/6 - 1/6
x = 35/6
x = 5 5/6

The correct result would be C. x = 5 5/6.

5 0

3 years ago

Find the sum. Write your answer in standard form.<br> (7x +13) + (x3 + 4x2 – 8)

mel-nik [20]

Answer:

. Simplify: (4x2 - 2x) - (-5x2 - 8x).

Solution:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2) Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve the system <br><br><br> x - 2y = -6<br> 3x + y = -4

stepan [7]

{x-2y=-6

{3x+y=-4 /*2

{x-2y=-6

<u>{6x+2y=-8 </u> (+)

7x=-14 /:7

x=-2

3x+y=-4

3*(-2)+y=-4

-6+y=-4

y=2

Solution: (-2; 2)

5 0

4 years ago

Which shows the terms of the series? 4 12 48 192 4 12 36 3 12 48 192 3 12 48

Stells [14]

The value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

<h3>What is summation?</h3>

In mathematics, the summation is the addition of a sequence of any kind of numbers, called addends or summands.

Now we have a given term

$\sum_{n=1}^{4} 3(4)^{n-1}$

By solving the above term;

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^{1-1}+3(4)^{2-1}+3(4)^{3-1}+3(4)^{4-1}$

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^0+3(4)^1+3(4)^2+3(4)^3$

$\sum_{n=1}^{4} 3(4)^{n-1}=3 + 12 +48 + 192$

Hence the value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

To know more about Summation follow

brainly.com/question/2767605

5 0

2 years ago

Find three pairs of equivalent fractions

Mrrafil [7]

1/3 : 2/6
1/2 : 2/4
15/31 : 45/93

hope this helps (;

7 0

3 years ago

Read 2 more answers