They are able to have the same value as the negative sign is simply transferred to the inside. Either way 4 is being subtracted from 3.

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>
What is the 5th term of an AP 2 , 14 ....98 .
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

- <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>
<h3><u>Solution </u><u>:</u><u>-</u></h3>
<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>
<u>Therefore</u><u>, </u>
<u>Here</u><u>, </u>
Common difference of an AP



Thus, The common difference is 12
<u>Now</u><u>, </u>
We know that,





Hence, The 5th term of given AP is 50
Answer:
B. The average quantity of detergent put into a box by a filling machine greater than one pound
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean. From the case above option B "The average quantity of detergent put into a box by a filling machine greater than one pound" tries to establish a difference between the variable ("quantity of detergent put into a box by a filling machine") is different from its average/mean
Determined by the signs multiplication is × or using it or could be 2 numbers attached like this 2y but for deciding it's a ÷ or / but that is some of the signs
Answer:x=63.4° y= 8.16
Step-by-step explanation: