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Fittoniya [83]
3 years ago
13

Write an exponential function for the following situation: Mr. Brinton is thinking of buying a new car. He is having a hard time

with this because the car he is looking at will depreciate 11% each year. If the car he is looking at is priced at $43,000 write an equation to model the situation
Mathematics
1 answer:
Sloan [31]3 years ago
7 0

Answer:

the answer s hard

Step-by-step explanation:

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Find expressions for the partial derivatives of the following functions:
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Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

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Which number is the median? 5, 15, 16, 20, 21, 21, 23, 23, 23, 26, 26, 26, 26, 27, 27, 29, 29, 29, 29, 29, 30, 30, 30, 30
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Answer:

median is 26

Step-by-step explanation:

26+26=52

52÷2=26

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Step-by-step explanation:

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PLEASE HELP ME!!!! WILL GIVE 5 STAR, THX, AND BRAINLIEST!!
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E fs ik that for a fact and maybe that’s all?
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