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mariarad [96]
3 years ago
10

An ecologist studies a forest area for evidence of competition among organisms. She chooses a specific location where a tree was

struck by lightning. The lightning strike caused the tree to fall over, leaving a space in the tree canopy for light to pass through. Which of these observations provides the best evidence of competition?
Many tree seedlings crowd the open space and attempt to grow in the sunlight.


Snakes come into the open space and eat small rodents that can easily be spotted in the sunlight.


Termites, with microorganisms in their stomachs to help them digest wood, are found on the fallen tree.


A type of plant, called a bromeliad, grows in the branches of the fallen tree and continues to survive even though the tree has fallen
Physics
2 answers:
-Dominant- [34]3 years ago
4 0

Answer:

Many tree seedlings crowd the open space and attempt to grow in the sunlight.

Mumz [18]3 years ago
3 0

Answer:

A

Explanation:

Many tree seedlings crowd the open space and attempt to grown in the sunlight.

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You roll a bowling ball down the lane and it takes 23 seconds to reach the pins. What is the total time it takes the ball to mov
Goryan [66]

Answer:

B. 23s

Explanation:

7 0
3 years ago
Read 2 more answers
A 120 g, 8.0-cm-diameter gyroscope is spun at 1000 rpm and allowed to precess. What is the precession period?
dolphi86 [110]

To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

I = MR^2

Here,

M = Mass

R = Radius of the hoop

The precession frequency is given as

\Omega = \frac{Mgd}{I\omega}

Here,

M = Mass

g= Acceleration due to gravity

d = Distance of center of mass from pivot

I = Moment of inertia

\omega= Angular velocity

Replacing the value for moment of inertia

\Omega= \frac{MgR}{MR^2 \omega}

\Omega = \frac{g}{R\omega}

The value for our angular velocity is not in SI, then

\omega = 1000rpm (\frac{2\pi rad}{1 rev})(\frac{1min}{60s})

\omega = 104.7rad/s

Replacing our values we have that

\Omega = \frac{9.8m/s^2}{(8*10^{-2}m)(104.7rad)}

\Omega = 1.17rad/s

The precession frequency is

\Omega = \frac{2\pi rad}{T}

T = \frac{2\pi rad}{\Omega}

T = \frac{2\pi}{1.17}

T = 5.4 s

Therefore the precession period is 5.4s

7 0
2 years ago
When a 70 kg man sits on the stool, by what percent does the length of the legs decrease? Assume, for simplicity, that the stool
allochka39001 [22]

The diameter of one leg of the stool is missing and it's 2cm.

Answer:

(ΔL/L) = 0.00729%

Explanation:

If the Weight of the man is W, the weight will be distributed equally on the 3 legs and so the reactions for each leg will be W/3 or F/3.

Now, Youngs modulus(Y) of douglas fir wood is about 1.3 x 10^(10) N/m^2. Gotten from youngs modulus of common materials.

Now, weight of man is 70kg.

Now diameter of one leg is 2cm.so radius of one leg = 2/2 = 1cm = 1 x 10^(-2)m

Area for one leg is; π( 1 x 10^(-2)m)^2 = 3.14 x 10^(-4)m

Now as stated earlier, the force on one leg is; F/3.

Now F = mg = 70 x 9.81 = 686.7N

So, force on one leg = 686.7/3 = 228. 9N

Now we know youngs modulus(Y) = Stress/Strain.

Stress = F/A while Strain = ΔL/L

Therefore Y = (F/A) / (ΔL/L)

And therefore, (ΔL/L) = F/(AY)

So (ΔL/L) = 228.9/(3.14 x 10^(-4))x(1.3 x 10^(10)) = 7. 29 x 10^(-5)

When expressed in percentage, it becomes 0.00729%

7 0
3 years ago
. A 13-g goldfinch has a speed of 8.5 m/s. What is its kinetic energy?
lesya692 [45]
PLEASE PRESS THE “Thanks!” BUTTON! :)
13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J
3 0
2 years ago
If the lights are off in a room and there are no windows, why do most objects appear black?
julsineya [31]
Because there are no windows.
6 0
3 years ago
Read 2 more answers
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