Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s
Answer:
Explanation:
Given
mass of crane ![m=1400\ kg](https://tex.z-dn.net/?f=m%3D1400%5C%20kg)
distance moved ![d=40\ m](https://tex.z-dn.net/?f=d%3D40%5C%20m)
Since it is moving with a constant velocity therefore net force on it is zero
Tension force=weight
T=mg
Work done by Tension T is
![W_T=T\cdot d](https://tex.z-dn.net/?f=W_T%3DT%5Ccdot%20d)
![W_T=1400\times 9.8\cdot 40](https://tex.z-dn.net/?f=W_T%3D1400%5Ctimes%209.8%5Ccdot%2040)
![W_T=548.8\ KJ](https://tex.z-dn.net/?f=W_T%3D548.8%5C%20KJ)
Work done by Gravity will be equal in magnitude but opposite in sign and can be obtained by work energy theorem which states that change in kinetic energy of object is equal to work done by all the forces
![W_T+W_g=0](https://tex.z-dn.net/?f=W_T%2BW_g%3D0)
![W_g=-548.8\ KJ](https://tex.z-dn.net/?f=W_g%3D-548.8%5C%20KJ)
The sun produces energy by converting gravitational potential energy into radiation via quantum processes in the nucleus of the atoms.
Since the mass of the sun and it's temperature are not quite enough to generate nuclear FUSION on their own, quantum tunneling is the primary process by which nuclear fusion occurs in our sun, SOL. FISSION also occurs as a result of this fusion.
Additionally, gravitational potential energy is also the reason that supernovae are so bright. Cool!
Respiratory system.
Oversimplified Explanation: they enter the lungs, which is part of the respiratory system.
Answer:
speed of golf ball is 1.15 ×
m/s
and % of uncertainty in speed = 2.07 ×
%
Explanation:
given data
mass = 45.9 gram = 0.0459 kg
speed = 200 km/hr = 55.5 m/s
uncertainty position Δx = 1 mm =
m
to find out
speed of the golf ball and % of speed of the golf ball
solution
we will apply here heisenberg uncertainty principle that is
uncertainty position ×uncertainty momentum ≥
......1
Δx × ΔPx ≥
here uncertainty momentum ΔPx = mΔVx
and uncertainty velocity = ΔVx
and h = 6.626 ×
Js
so put here all these value in equation 1
× 0.0459 × ΔVx = ![\frac{6.626*10^{-34}}{4\pi }](https://tex.z-dn.net/?f=%5Cfrac%7B6.626%2A10%5E%7B-34%7D%7D%7B4%5Cpi%20%7D)
ΔVx = 1.15 ×
m/s
and
so % of uncertainty in speed = ΔV / m
% of uncertainty in speed = 1.15 ×
/ 55.5
% of uncertainty in speed = 2.07 ×
%