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Nostrana [21]
3 years ago
5

Two long, parallel wires are separated by a distance of 2.60 cm. The force per unit length that each wire exerts on the other is

4.30×10^−5 N/m, and the wires repel each other. The current in one wire is 0.520 A.Required:a. What is the current in the second wire? b. Are the two currents in the same direction or in opposite directions?
Physics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

<em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires</em>

Explanation:

Force per unit length on the wires = 4.30×10^−5 N/m

distance between wires = 2.6 cm = 0.026 m

current through one wire = 0.52 A

current on the other wire = ?

Recall that the force per unit length of two wires conducting and lying parallel and close to each other is given as

F/l = \frac{u_{0}I_{1} I_{2}  }{2\pi r }

where F/l is the force per unit length on the wires

u_{0} = permeability of vacuum = 4π × 10^−7 T-m/A

I_{1} = current on the first wire = 0.520 A

I_{2} = current on the other wire = ?

r = the distance between the two wire = 0.026 m

substituting the value into the equation, we have

4.30×10^−5 = \frac{4\pi *10^{-7}*0.520*I_{2}  }{2\pi *0.026} =  \frac{ 2*10^{-7}*0.520*I_{2}  }{0.026}

4.30×10^−5 = 4 x 10^-6 I_{2}

I_{2} = (4.30×10^-5)/(4 x 10^-6) = <em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires.</em>

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