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3 years ago

A sound wave increases in pitch. Which of the following changes has occurred?

Physics

1 answer:

statuscvo [17]3 years ago

6 0

If the pitch of a sound increased, then the wave frequency increased. (D)

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In which of the following situations would convection currents most likely occur?

poizon [28]

Answer: Option (B) is the correct answer.

Explanation:

Convection is defined as a process in which a fluid (liquid or gas) is heated and the cooler liquid (more dense) settles or sinks at the bottom whereas a hotter material (less dense) will rises to the top.

For example, ice being less dense (cooler material) will float in a lake whereas liquid water being more dense will sink at the bottom.

Thus, we can conclude that situation in which convection currents most likely occur is within the water in a lake as ice forms on the top.

4 0

3 years ago

Read 2 more answers

How does the voltage applied to the electric motor affect the coil's number of rotations and its rotational direction

sleet_krkn [62]

Higher voltage means faster rotation. Changing the voltage polarity changes the direction of the motor.

3 0

3 years ago

Questions 2. Rewrite the following quantities using suitable prefixes 5000 000

Rufina [12.5K]

Ans. 5 X 10^6

Explanation:

Here,^ represents 6 times 10 and 5 is multiplied. That is 5000 000.

Hope this helps

5 0

3 years ago

A rock is thrown horizontally from a bridge with a velocity of 17.0 m/s. It takes the rock 3.0 s to strike the water below. What

zalisa [80]

Answer:

V= 33.98 m/s

Explanation:

Given that

Horizontal speed ,u= 17 m/s

Time taken by rockets to strike the water ,t= 3 s

We know that acceleration due to gravity ,g= 9.81 m/s²

There is no any acceleration in the horizontal direction that is why the horizontal veloity will remain constant.

In the vertical direction

vy = uy+ g t

Initial velocity in vertical direction is 0 m/s.

vy= 0+ 9.81 x 3

vy = 29.43 m/s

The resultant velocity

$V=\sqrt{v_y^2+u^2}$

$V=\sqrt{29.43^2+17^2}\ m/s$

V= 33.98 m/s

7 0

3 years ago

A reconnaissance plane flies 556 km away from

9966 [12]

We use the formula, to calculate the average speed of the round trip,

$v_{av} =\frac{d_{total}}{t_{total}}$

Here, $d_{total}$ , is total distance covered by plane in total time, $t_{total}$ .

For the round trip,

$d_{total=556\ km+556\ km=1112 \times 10^3\ m$

$t_{total}=\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}$ .

Thus,

$v_{av} =\frac{1112 \times 10^3\ m}{\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}} =\frac{1112 \times 10^3\ m}{668.26\ s+445.51\s} \\\\v_{av}=998.41\ m/s$ .

5 0

3 years ago