Velocity = distance / time
v = (15*1000)m / (2*60*60)s
v=2.08 m / s
Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm .Ultraviolet wave is used by doctors in order to keep the wounds away from bacteria.
<h3>What is ultravoilent wave ?</h3>
Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm. Ultravoilent wave is directly comes frim the sun. It is classified into the UV(A) , UV(B),UV(B).
Ultravoilet rays also effects the human eyes that s why sun glasses are used. The experiments here are compared and quantified to the effectiveness of the sunscreens with various strengths.
To learn more about the ultravoilent wave refr to the link;
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Answer:
E) The centripetal force is always perpendicular to the velocity.
Explanation:
Due to gravity and inertia, the satellite follows a uniform circular motion. In this movement, the velocity is always tangent to the orbit and the centripetal force is directed towards the center. Therefore, there is no net acceleration in the same direction of velocity, which implies that it remains constant.
Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>

= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>

=
= 3658.836 lb.in
=
lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>

= 
= 3334.8 lb.in
=
lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>

= 
= 4023.061 lb. ft/s
=
hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>

= 
= 3666.804 lb.ft /s
=
hp
= 6.667 hp
The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
= 
= 23.04/10.3
= 2.23 m/s²
It continues to fly but now with some tangential acceleration
= 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
= 
= 
= 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
learn more about acceleration here :
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