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3 years ago

12

The formula can be used to convert temperatures between degrees Fahrenheit () and degrees Celsius (). How many degrees are in th

e Celsius equivalent of -22 F

1 answer:

Jlenok [28]3 years ago

8 0

Answer:

-30°C

Explanation:

F-32/180 =C-0/100

or, -22-32/180=C/100

or, -54/180*100=C

or, -0.3*100=C

therefore, C= -30

-22°F = -30°C

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For our statistical definition of entropy, we use the equation S = klnW. In this equation, what does k represent?

Sloan [31]

<span>In the </span>natural logarithm<span> format or in equivalent notation (see: </span>logarithm) as:

base<span> e</span><span> assumed, is called the </span>Planck entropy<span>, </span>Boltzmann entropy<span>, Boltzmann entropy formula, or </span>Boltzmann-Planck entropy formula<span>, a </span>statistical mechanics<span>, </span><span> </span>S<span> is the </span>entropy<span> of an </span>ideal gas system<span>, </span>k<span> is the </span>Boltzmann constant<span> (ideal </span>gas constant R<span> divided by </span>Avogadro's number N<span>), and </span>W<span>, from the German Wahrscheinlichkeit (var-SHINE-leash-kite), meaning probability, often referred to as </span>multiplicity<span> (in English), is the number of “</span>states<span>” (often modeled as quantum states), or "complexions", the </span>particles<span> or </span>entities<span> of the system can be found in according to the various </span>energies<span> with which they may each be assigned; wherein the particles of the system are assumed to have uncorrelated velocities and thus abide by the </span>Boltzmann chaos assumption<span>.

I hope this helps. </span>

7 0

3 years ago

A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex

Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

$\text{Efficiency of the heat engine} = \eta = 26\% = 0.26$

$\text{Energy taken in by the heat engine during each cycle} = Q_h$

$\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J$

$\eta = 1 - \frac{Q_{c}}{Q_{h}}$

$0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}$

$\frac{8.55* 10^{3}}{Q_{h}} = 0.74$

$Q_h = \frac{8.55*10^3}{0.74}$

$Q_h = 11.554*10^3J$

PART A)

Work done by the heat engine in each cycle = W

$W = Q_h-Q_c$

$W = 11.554*10^3J-8.55*10^3J$

$W = 3004J$

According to the value given we have that,

$P = 4.0kW$

$P = 4000W$

Power is defined as the variation of energy as a function of time therefore,

$P = \frac{W}{t}$

$4000W = \frac{3004J}{t}$

$t = \frac{3004}{4000}$

$t = 0.75s$

Therefore the interval for each cycle is 0.75s

5 0

3 years ago

A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula

Marina86 [1]

Answer: $\alpha =10.66 rad/s^2$

Explanation:

Given

mass of disk $m=5 kg$

diameter of disc $d=30 cm$

Force applied $F=4 N$

Now this force will Produce a torque of magnitude

$T=F\cdot r$

$T=4\dot 0.15$

$T=0.6 N-m$

And Torque is given Product of moment of inertia and angular acceleration $(\alpha )$

$T=I\cdot \alpha$

Moment of inertia for Disc $I= \frac{Mr^2}{2}$

$I=0.05625 kg-m^2$

$0.6=0.05625\cdot \alpha$

$\alpha =10.66 rad/s^2$

3 0

3 years ago

Difference beteween phycial change and chemical change

pychu [463]

Answer:

Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.

4 0

3 years ago

In a standard tensile test a steel rod of 22-mm diameter is subjected to a tension force of 75kN. Knowing that v = 0.30 and E =

Mazyrski [523]

Answer:

(a) Elongation of rod = 0.19732 mm

(b) Change in diameter = 0.00651 mm

Explanation:

Circular area at end of steel rod = pi * diameter^2 / 4

$Area = pi * (22 * 10^-^3)/4$

Area = 3.801 * 10^(-4) meter squared

Stress = force / area

Stress = 75000 / (3.801 * 10^-4)

Stress = 197316495 Pa OR 0.197 GPa

Modulus of elasticity = stress / strain

200 = 0.19732 / Strain

Strain = 0.0009866 (longitudinal)

(a) Strain = change in length / initial length

0.0009866 = Elongation of rod / 200

Elongation of rod = 0.19732 mm

(b) Poisson ratio = lateral strain / longitudinal strain

0.3 = lateral strain / 0.0009866

Lateral strain = 0.000296

Lateral strain = Change in diameter / original diameter

0.000296 = Change in diameter / 22

Change in diameter = 0.00651 mm

3 0

3 years ago

Read 2 more answers