A rocket is dropped out of an airplane at 100 m/s (downward). If the rocket fires causing an upward acceleration of Ct2 and it t
akes 20 seconds to reach zero velocity, what is the value of C?
1 answer:
Answer:
C = 0.0125 m/s⁴. The calculation procedure can be found in the attachment below. The concept of motion along a straight line with constant acceleration has been applied to solve the problem.
Explanation:
The sign convention chosen in this problem solution is upwards as positive and downwards negative. The equation of motion v = u + at has been used to calculate the constant C as only one unknown is contained in this equation. This is so because we have been given the initial velocity, the acceleration and the time taken. To solve future problems of this kind, first thing to check for is an equation of motion with the least number of unknown. This helps to reduce the complexity of the problem solution.
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while if we need to find the area of the graph then it is integral of quantity on Y axis with respect to x axis
A. The area under that object's velocity-time graph
this shows area of velocity time graph = = displacement
so its not correct
B. The slope of that object's position-time graph
This shows slope of position time graph = = velocity
so this is correct for velocity
C. The slope of that object's velocity-time graph
This shows slope of velocity time graph = = acceleration
D. The area under that object's position-time graph
this shows the area of position time graph =
this is no physical quantity
So option B is correct
Answer:
d. (1/8πε0)Q/a
Explanation:
The potential difference
Suppose we separate the quantity which is dimensionally and equally the same as
. Then, we will have
and
as the same dimension.
Therefore, the correct option is:
d. (1/8πε0)Q/a