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Cerrena [4.2K]
3 years ago
8

A speed of 55 miles per hour is equal to how many feet per minute?

Mathematics
2 answers:
den301095 [7]3 years ago
7 0
The answer is 4840 hope this helps
Alex17521 [72]3 years ago
6 0

We know that

1 miles =5280 feet

1 hour=60 minutes

so, we can write

55\frac{miles}{hour} =55\frac{5280 feet}{60 minutes}

so, we can write it as

55\frac{miles}{hour} =55*\frac{5280 }{60}*\frac{feet }{minutes}

55\frac{miles}{hour} =55*\frac{5280 }{60}*\frac{feet }{minutes}

now, we can simplify it

and we get

55\frac{miles}{hour} =4840\frac{feet }{minutes}...........Answer

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mixer [17]

Answer:

x = 20

Step-by-step explanation:

The angles shown are alternate exterior angles.

Alternate exterior angles are congruent

This means that 46 must equal 3x - 14

Note that we've just created an equation that we can use to solve for

We now use the equation to solve for x

3x - 14 = 46

add 14 to both sides

3x - 14 + 14 = 46 + 14

simplify

3x = 60

Divide both sides by 3

3x / 3 = x

60 / 3 = 20

We get that x = 20

4 0
2 years ago
When factored completely the expression p^4-81 is equivalent to
spayn [35]
   
\displaystyle\\
p^4 - 81 =\\\\
 =p^4-3^4 =\\\\
= \Big(p^2\Big)^2 - \Big(3^2\Big)^2 =\\\\
=\Big(p^2+3^2\Big)\Big(p^2-3^2\Big)=\\\\
=\boxed{\bf \Big(p^2+3^2\Big)\Big(p+3\Big)\Big(p-3\Big)}



7 0
3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
PLZ HELP, WILL MARK BRAINLIEST
andreev551 [17]

220.5

i dont know how to show my work sorry :) hope it helps

3 0
3 years ago
I need your help ASAP!
slega [8]

Answer:

C.

Step-by-step explanation:

If 4ab+k=13 then k=13-4ab

8 0
3 years ago
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