3 years ago

10a - 25 + 56 need help asap

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

5 0

Answer:

10a+31 is the simplified version but if you are trying to ask 10a-25=56 your answer would be 8.1

Step-by-step explanation:

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Sharon is buying candy. she buys 5 type on the menu if she splits the price equality with four friends how mich do they each pay

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D. 0.65

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3 years ago

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vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

10a - 25 + 56 need help asap​

10a - 25 + 56 need help asap