Answer:
The specific heat of the metal is 0.212 J/(g°C).
Explanation:
We can calculate the specific heat of the metal by the following equilibrium:
In the above equation, we have that the heat loses by the metal (b) is gained by the water (a).
: is the water's mass = 72.0 g
: is the specific heat of water = 4.184 J/(g°C)
: is the initial temperature of the water = 19.2 °C
: is the final temperature of the water = 25.5 °C
: is the metal's mass = 141 g
: is the specific heat of metal =?
: is the initial temperature of the metal = 89.0 °C
: is the final temperature of the water = 25.5 °C
Therefore, the specific heat of the metal is 0.212 J/(g°C).
I hope it helps you!
Is there a picture for that
Answer:
237.5 K.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 5.2 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = 4.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = ??? K).
∴ T = PV/nR = (5.2 atm)(15.0 L)/(4.0 mol)(0.0821 L.atm/mol.K) = 237.5 K.
Answer:
Layer D
Explanation:
First means older.
Rock E is an intrusion, so it is younger than all the layers it pass through. Apparently, Rock E is the youngest layer. So, Layer D is came before Layer E.
Hope this helps!
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