The shortest wavelengths occur in the:

Chemistry

1 answer:

kaheart [24]3 years ago

6 0

Answer:

1) blue end of the spectrum

2) area of aperture

Explanation:

1) The electromagnetic spectrum encompases a wide range of frequency (ν) and wavelength (λ) that includes gamma rays, x-rays, ultra violet(UV), visible, infra red (IR), microwaves and radiowaves. The wavelength increases from gamma rays to radio waves.

The wavelength perceivable by human eyes lies in the UV-visible region which extends from 380 nm in the blue to 740 nm in the red.The shortest wavelengths occur in the blue end of the spectrum which also have the highest energy. In contrast, longer wavelengths occur on the red which have lower energy.

2) The light gathering capacity of a telescope is dependent upon its area of aperture. Larger the area, greater is the light gathering power which implies that the telescope has the capability of detecting weak or faint objects.

The area of the aperture is essentially the area of the objective of the telescopic lens which is given as:

$area = \frac{\pi*D^{2} }{4}$

where D = diameter of the lens

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The half life of a scandium-46 is 84 days. The scandium-46 is used in oil refining as a tracer to monitor the oil movement and it emits extremely high energetic gamma/beta radiation. So the half-life of the radioisotope scandium-46 is 84 days. The Scandium 46 created by neutron activation, is a synthetic isotope of Scandium.

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Sodium combines with water to produce sodium hydroxide and hydrogen gas. Which word equation represents this violent reaction?

Natalka [10]

Answer: sodium + water → sodium hydroxide + hydrogen

Explanation:

1) The first part of the statment "sodium combines with water" means that these two pure substances are the reactants.

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Na(s) + H₂O (l) → NaOH(aq) + H₂(g).

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Read 2 more answers

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$