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3 years ago

Please help! Question above

Mathematics

1 answer:

Romashka [77]3 years ago

8 0

2nd answer is corrrrrect

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Divide mentally. 8.4 ÷ 4,000 = ? A. 0.021 B. 0.0021 C. 0.00021 D. 0.000021 please explaine fully cuz i dont know help hurry

stealth61 [152]

It's B, and being mental won' help when having a calculator next to you) It's B for sure!!!

6 0

3 years ago

Read 2 more answers

Y = 6x; (2,12) tell weather the ordered pair is a solution of the equation

svet-max [94.6K]

Hi!

I can help you with joy!

Plug in the values and solve:
Instead of y, plug in 12 (the y-coordinate)
Instead of x, plug in 2 (the x-coordinate)
Then, if we end up with a true statement, then the ordered pair is a solution of the equation.
12=6(2)
12=12
Yeah! It worked! :)

<u>Answer:</u>

Yes, (2,12) is a solution of the equation y=6x.

Hope it helps.

Do comment if you have any queries regarding my answer.

~Misty~

7 0

3 years ago

The price of a car decreases by 35% to £13000.<br><br> What was the car worth before the decrease?

Tpy6a [65]

Answer:

20000

Step-by-step explanation:

13000/.65=20000

3 0

3 years ago

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

$x^2 + 5x -300=0$ (3)

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

$L = x + 5$

$L = 15 + 5$

$L = 20\ in$

8 0

4 years ago

Find the area of the trapezoid.

Lemur [1.5K]

Answer:

448

Step-by-step explanation:

A=((a+b)/2) h=(17+39)/2·16=448

8 0

3 years ago