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neonofarm [45]
3 years ago
5

The table of values represents a polynomial function ​f(x)​.

Mathematics
2 answers:
Olegator [25]3 years ago
5 0

Answer:

336

This is the correct answer because I just took the test! Good luck!

Flura [38]3 years ago
4 0
1 that’s exactly but 67
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Find the diameter of a cicle with an area of 240.48 π square millimeters?
seropon [69]

31.02 mm.

Step-by-step explanation:

Step 1:

The area of the given circle is 240.48 π sq mm

We need to find the diameter of the circle

Step 2:

The formula for obtaining the area of any circle is π*r² where r represents the radius of the circle

We know that the diameter of  circle is 2 times its radius.

Hence equating the formula of the area of the circle to the given value we can find its radius. Then multiplying the radius by 2 , we get the diameter.

Step 3 :

Using the above method , we have

πr²  = 240.48 π

=> r² = 240.48 π / π = 240.48

=> r = √240.48 = 15.51 approximately

Hence the diameter of the given circle is 2 * 15.51 = 31.02 mm.

6 0
3 years ago
Match each Situation to one of the equations
Elis [28]

Answer:

A: y = -2x

B: rate(meters/time)= 12 meters(distance) ÷ 2 minutes(time)

Step-by-step explanation:

5 0
3 years ago
A cargo ship is carrying nine shipping crates. Each rate is equal in , and the
Korolek [52]
The answer is 523 because 4,707 divide 9 to be equal numbers for each one I hope it helps
6 0
3 years ago
30=11+3x find x need asap
kompoz [17]

Answer:

x = 19/3

Step-by-step explanation:

30 - 11 = 3x

3x = 19

x = 19/3

hope it helps!

4 0
3 years ago
Read 2 more answers
The following data lists the ages of a random selection of actresses when they won an award in the category of Best​ Actress, al
Valentin [98]

Answer:

a) p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

b) The 99% confidence interval would be given by (-21.469;2.069)

c) We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two

Step-by-step explanation:

Part a

Let put some notation  

x=actor's age , y = actress's age

x: 58 41 36 36 34 33 48 37 37 43

y: 26 27 34 26 35 29 23 42 30 34

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \geq 0

Alternative hypothesis: \mu_y -\mu_x

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: -32, -14, -2, -10, 1, -4, -25, 5, -7, -9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= -9.7

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =11.451

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-9.7 -0}{\frac{11.451}{\sqrt{10}}}=-2.679

The next step is calculate the degrees of freedom given by:

df=n-1=10-1=9

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,9)".And we see that t_{\alpha/2}=3.25  

Now we have everything in order to replace into formula (1):  

-9.7-3.25\frac{11.451}{\sqrt{10}}=-21.469  

-9.7+3.25\frac{11.451}{\sqrt{10}}=2.069  

So on this case the 99% confidence interval would be given by (-21.469;2.069)

Part c

We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two means is 0.

8 0
3 years ago
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