6 watermelons, because each watermelon is 2 kg
3 1/4 = 3.25
-2 2/3 = -2.6667
3.25 + (- 2.6667)
= 3.25 - 2.6667
= ~0.58
therefore best estimate is 0
- Sample space = {TT, HH, TH, HT} where T is tail and H is head.
- Number of outcomes = 4
- The probability of getting two heads on tossing two coins

<u>Answer</u><u>:</u>
<u>D)</u><u> </u><u>2</u><u>5</u><u>%</u>
Hope you could understand.
If you have any query, feel free to ask.