Since we want just the top 20% applicants and the data is normally distributed, we can use a z-score table to check the z-score that gives this percentage.
The z-score table usually shows the percentage for the values below a certain z-score, but since the whole distribution accounts to 100%, we can do the following.
We want a z* such that:
But, to use a value that is in a z-score table, we do the following:
So, we want a z-score that give a percentage of 80% for the value below it.
Using the z-score table or a z-score calculator, we can see that:
![\begin{gathered} P(zNow that we have the z-score cutoff, we can convert it to the score cutoff by using:[tex]z=\frac{x-\mu}{\sigma}\Longrightarrow x=z\sigma+\mu](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28zNow%20that%20we%20have%20the%20z-score%20cutoff%2C%20we%20can%20convert%20it%20to%20the%20score%20cutoff%20by%20using%3A%5Btex%5Dz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5CLongrightarrow%20x%3Dz%5Csigma%2B%5Cmu)
Where z is the z-score we have, μ is the mean and σ is the standard deviation, so:
so, the cutoff score is approximately 72.
Answer:
domain is (xo ≤ x ≤ 0.45 )
range is (xo ≤ y ≤ 8.1 )
Step-by-step explanation:
given data
constant speed = 18 miles per hour
total time = 27 minutes = 0.45 hour
solution
we consider here Domain number of hours = x and Range distance traveled = y
we apply here distanace formula that is
Distance = speed × time .........................1
put here value
Distance = 18 × 0.45 = 8.1 miles
and no of hours x = 0 to 0.45 hours
so here
So domain is (xo ≤ x ≤ 0.45 )
and
Distance is 0 to 8.1 miles
So range is (xo ≤ y ≤ 8.1 )
Linear not sure ...........
Answer:
4x 3 - 6 4 is the answer
Step-by-step explanation:
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