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MariettaO [177]
3 years ago
14

kendra needs 1/3 cup of nuts for a cake she ia baking .if she had 8 cups of nuts how many cakes could she make

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

2 2/3

Step-by-step explanation:

well needs  1/3 cups for a cake and she only has 8 cups, so just multiply,

1/3x8=2 2/3

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Substitution Method. Help please? #5 please!
s344n2d4d5 [400]
Switch the second equation to equal y so...
y=-2x-3
then plug in for y in the first equation
2x+4(-2x-3)=6
2x-8x-12=6
-6x=18
x=-3
now plug in for y
2(-3)+y=-3
-6+y=-3
y=3

answer (-3,3)
8 0
3 years ago
Plz help!!!
jeka94

Answer:

Yes Billy is correct

Step-by-step explanation:

Think of a pizza in 4 peices on pizza had 1 clice taken out from 4 and one has 3 pieces have been taken away from 4. So therfore -3/4 is less.

8 0
3 years ago
Read 2 more answers
Kyle is 12 years older than Susan. Last year, he was twice as old as Susan.
iogann1982 [59]

Answer:

13 and 25

Step-by-step explanation:

um so dont hold me to this, but if he's twelve years older than susan she would've been twelve and he would've been 24 last year.

3 0
3 years ago
A researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic
Delvig [45]

Answer:

90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

Step-by-step explanation:

We are given that a researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic meter with a standard deviation of 0.093.

Firstly, the pivotal quantity for 90% confidence interval for the population mean iron concentration is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean iron concentration = 0.802 cc/cubic meter

             s = sample standard deviation = 0.093

             n = number of water samples = 27

             \mu = population mean

<em>Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 90% confidence interval for the population mean, \mu is ;

P(-1.706 < t_2_6 < 1.706) = 0.90  {As the critical value of t at 26 degree of

                                                 freedom are -1.706 & 1.706 with P = 5%}

P(-1.706 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 1.706) = 0.90

P( -1.706 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 1.706 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X -1.706 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +1.706 \times {\frac{s}{\sqrt{n} } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X -1.706 \times {\frac{s}{\sqrt{n} } , \bar X +1.706 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 0.802 -1.706 \times {\frac{0.093}{\sqrt{27} } , 0.802 +1.706 \times {\frac{0.093}{\sqrt{27} } ]

                                                 = [0.771 , 0.832]

Therefore, 90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

4 0
3 years ago
Find the annual interest rate.
slega [8]

The annual interest rate is 3.5%.

Solution:

Given Interest (I) = $26.25

Principal (P) = $500

Time (t) = 18 months

Rate of interest (r) = ?

Time must be in years to find the rate per annum.

1 year = 12 months

Divide the time by 12.

Time (t) = \frac{18}{12}=\frac{3}{2} years

Now, find the rate of interest using simple interest formula.

<u>Simple interest formula:</u>

$I=\frac{Prt}{100}

$26.25=\frac{500\times r\times \frac{3}{2} }{100}

$26.25\times 100 =500\times r\times \frac{3}{2}

$2625 =250\times r\times 3

$2625 =750\times r

$\Rightarrow r=\frac{2625}{750}

⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

8 0
3 years ago
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