Answer:
the third answer
Step-by-step explanation:
hope it helps
If you were to use the substitution method to solve the following system, we need to write one of the equation to an <span>expression equivalent to y. Let us say the second equation, we write it as follows:
</span><span>6x – 3y = –3
-3y = -6x - 3
y = 2x + 1
We substitute the equation to the first given equation as follows:
</span><span>2x – 5y = –3
</span>2x – 5(2x + 1) = –3
2x - 10x - 5 = -3
-8x = 2
x = -1/4
y = 2(-1/4) + 1 = 1/2
Answer:
A.
Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.
Then apply point-slope form.
B. The answer is x = 6.
The midpoint of JK is
The line that goes through JK is just a horizontal line 
because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, 
.
Answer:
The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:
logb(a) = x ⇒ a = bˣ
So, for b = 0 ⇒ 0ˣ = a
And there is impossible, "a" only could be 0.
For b = 1 ⇒ 1ˣ = a
And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.
For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.
So, 0<b<1 and b >1.
Answer:
C-7.4
Step-by-step explanation:
just took the test EDG2020
