Answer:
Autotrophs
Explanation:
They are responsible for the production of food. Root words "auto" for self and "troph" for food.
Answer:
well for me
Explanation:
photosynthesis gives out oxygen so cellular respiration gives out carbon 4 oxide and take in oxygen
Answer:
potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol
to get 1000 ml
Molar concentration = Mass concentration/Molar Mass
mass concentration = molar concentration x molar mass
mass concentration=0.1 M,
molar mass= 204.233 g/mol
so to get 1L
mass conc = 204.233 x 0.1
= 20.4233g for 1L or 1000 ml
to get 6.00 ml
if 20.4233g is for 1000ml
then to 6.00 ml
= 20.4233 x 6 / 1000
= 0.123g for 6.00 ml
according to the equation below
NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)
number of moles of NaOH is equal to that of KHP
so the same amount will be needed too, which is
= 0.123g
<span>To determine if changing the egg size affects the drop height. hope this helps</span>
The answer is: [B]: 1.89 * 10²³ .
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PV = nRT ; is the equation for "STP" conditions; that is, the "ideal gas equation" .
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i.e. when Pressure, "P" = 1.00 atm;
Temperature, "T" = 273 K;
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R = the ideal gas constant = ((0.08206 L-atm/K-mol)
n = number of moles;
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So, we plug in our known values:
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<span>(1.00atm) (7.02L) = ("n" mol) (0.08206 L-atm/K-mol) (273K); </span>
<span>_____________________________________________
</span>→ 7.02 L·atm = (? mol) (22.4 L·<span>atm/mol) .
</span>
(Note that t<span>he Molar Volume of a gas at STP is a constant using Avogadro's value of </span>22.4 L / mol. 1 mol of any ideal gas at STP occupies 22.4 L. An ideal gas takes the shape of its container)..
<span>_______________________________________________________
</span> → Divide EACH side of the equation by "(22.4 L·atm/mol)" ;
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→ 7.02 L·atm / = ("n" mol) (22.4 L·atm/mol) ;
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→ 7.02 L·atm / (22.4 L·atm/mol) =
[("n" mol) (22.4 L·atm/mol)]/(22.4 L·atm/mol);
______________________________________________________
<span>to get:
_________________________________________________
</span>→ n = <span>0.313 mol ;
</span>_____________________________________________________
Note: 1 mole = 1 mol = 6.022 * 10²³ molecules.
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→ So, 0.313 mol Cl₂ (g) molecules * [(6.022 * 10²³ molecules) / (1 mol)] =
___________________________________________________________
→ [(0.313) * (6.022 *10²³) ] molecules of Cl₂ (g) ;
___________________________________________________________
→ = 1.88 * 10²³ molecules of Cl₂ g ;
___________________________________________________________
→ which most closely corresponds with answer choice:
___________________________________________________________
[B]: 1.89 * 10²³ .
___________________________________________________________
