<span>It relates the </span>measured<span> cell </span>potential<span> to the reaction quotient and allows the ... Substituting these expressions into Equation 20.6.</span>1<span>, we obtain ... the </span>standard<span> cell </span>potential<span> (E° cell), and the </span>reactant<span> and product concentrations at ... 0.013 </span>M, [Ce3+<span>] = 0.60 </span>M, [Cl−<span>] = 0.0030 </span>M, PC<span>l2 = 1.0 atm, and T = </span>25°C<span>.</span>
Answer:
One may conclude that they have an identical number of electrons in their outermost shell, therefore the can be substituted for one another.
Explanation:
Elements in the same family tend to behave similarly in chemical reactions because they have similar number of valence electrons in their outermost shell and they also have similar chemical properties.
Valence electrons are responsible for reactions between elements. The valence electron makes it possible for atoms to combine and react, therefore, elements in a family behave similarly in chemical reactions because they have an identical number of electrons in their outermost shell.
Answer:
grams of solute = 31.5 g
Explanation:
Given data:
Grams of solute = ?
%m/v = 3%
Volume = 1050 mL
Solution:
grams of solute = 3 g of NH₄Cl / 100 mL × 1050 mL
grams of solute = 0.03 g × 1050
grams of solute = 31.5 g
Answer:
The pressure of 0.5 mole of nitrogen gas=![168.78 k pa](https://tex.z-dn.net/?f=168.78%20k%20pa)
Given:
Moles of nitrogen gas=0.5mole
Volume of nitrogen gas=5L
Temperature of nitrogen gas=203K
To Find:
Pressure of 0.5g mole of nitrogen gas
<u>Step by Step by Explanation:</u>
Formula used for calculating the pressure of a gas is achieved through ideal gas equation
According to Ideal Gas;
From this above equation, pressure can be calculated as
![P=\frac{n R T}{V}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bn%20R%20T%7D%7BV%7D)
Where P=Pressure of the gas
N=number of moles=0.5moles
R=Gas constant![=8.3144598 L k p_{a} k^{-1} m o l^{-1}](https://tex.z-dn.net/?f=%3D8.3144598%20L%20k%20p_%7Ba%7D%20k%5E%7B-1%7D%20m%20o%20l%5E%7B-1%7D)
V=Volume of nitrogen gas in litres=5L
T=Temperature of nitrogen gas=203K
Substitute all the values in the above equation we get
![P=\frac{0.5 \times 8.3144598 \times 203}{5}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B0.5%20%5Ctimes%208.3144598%20%5Ctimes%20203%7D%7B5%7D)
![P=\frac{843.9177}{5}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B843.9177%7D%7B5%7D)
![P=168.78 k pa](https://tex.z-dn.net/?f=P%3D168.78%20k%20pa)
Result:
Thus the pressure of 0.5 mole of nitrogen gas is <u>
</u><u>
</u>
If X is an equivalent base to H₂O
HX is an equivalent acid to H₃O⁺
HX is a stronger acid than H₃O⁺
HX is not an acid
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
X⁻ is a weaker base than H₂O
X⁻ is not a base.
The correct response or this is
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺